Two cars, x travelling at an average speed of 40 km/h and y travelling at an average speed of 50 km/h start from the same point at the same time. If they travel in opposite directions, how far apart will they be after half an hour?

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Solution

Dear Student ,
Here in this case the car x moves with speed of 40 km/h and y moves with speed of 50 km/h .
Now, time taken by them is , t = half of an hour
$N o w t h e c a r x m o v e s i n h a l f a n h o u r i s, S_{x} = v_{x} t = 40 \times \frac{1}{2} = 20 k m A g a i n, c a r y m o v e s s i n h a l f a n h o u r i s, S_{y} = v_{y} t = 50 \times \frac{1}{2} = 25 k m N o w, a s t h e y s t a r t f r o m s a m e p o i n t a n d a t s a m e t i m e i n o p p o s i t e d i r e c t i o n s o, a f t e r h a l f a n h o u r d i \tan c e b e t w e e n t h e m i s, D = S_{x} + S_{y} = 20 + 25 = 45 k m$
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