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Two casks con...

Question

Two casks contain mixtures of petrol (P) and kerosene (K). in the first cask P:K=7:3 and in the second cask P:K= 3:1. in what ratio should the mixtures from the two casks be taken to give a mixture in which P:K is 11:4?

2:3

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2:2

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1:2

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1:3

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Solution

The correct option is B
2:2

Using alligation, we can directly solve this question

Take either petrol or kerosene.

Petrol in cask 1 = $\frac{7}{10}$

Petrol in cask 2 = $\frac{3}{4}$

Petrol in mixture = $\frac{11}{15}$

Ratio to take the mixture $= \frac{1}{60} : \frac{1}{30} = 1 : 2$

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Two casks contain mixtures of petrol (P) and kerosene (K). in the first cask P:K=7:3 and in the second cask P:K= 3:1. in what ratio should the mixtures from the two casks be taken to give a mixture in which P:K is 11:4?

The correct option is B 2:2 Using alligation, we can directly solve this question Take either petrol or kerosene. Petrol in cask 1 =710 Petrol in cask 2 =34 Petrol in mixture =1115 Ratio to take the mixture =160:130=1:2

The correct option is B
2:2

Using alligation, we can directly solve this question

Take either petrol or kerosene.

Petrol in cask 1 = $\frac{7}{10}$

Petrol in cask 2 = $\frac{3}{4}$

Petrol in mixture = $\frac{11}{15}$

Ratio to take the mixture $= \frac{1}{60} : \frac{1}{30} = 1 : 2$