Question

Two cells of $1.25V$ and $0.75V$ are connected in parallel. The effective voltage will be

Answer 1

Step 1: Given data

Voltages $E_1=1.25V$

$E_2=0.75V$

Let the resistance $R_1$ and $R_2$ is $1ohm$.

Step 2: To find

We have to find the effective voltage.

Step 3: Calculate effective voltage using Kirchoff’s rulesKirchhoff's Voltage Law states that the sum of voltages in a loop is zero. where n is the number of element voltages measured around the loop.

$E_{eff}=\frac{E_1{R}_2+E_2{R}_1}{R_1+R_2}$

By substituting the values,

$$\begin{gathered} =\frac{1.25\times 1+0.75\times 1}{1+1} \\ =\frac{2}{2} \\ =1V \end{gathered}$$

Hence, effective voltage is $1\text{V}$.