Two cells of e.m.f. E1 and E2 are joined in series and balancing length of the potentiometer wire is 625 cm. If the terminals of E1 are reversed, the balancing length obtained is 125 cm. Given E2>E1, the ratio E1:E2 is ?
A
2:3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
5:1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3:2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
1:5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C3:2 We know that in potentiometer voltage is directly proportional to balancing length
if both cell with same polarity connected in series then,
E1+E2=625
if both cell with opposite polarity connected in series then,