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Question

Two cells of same emf E but of different internal resistance r1 and r2 are connected in series with an external resistance R. The potential drop across the first cell is found to be zero. The external resistance R is

A
r1+r2
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B
r1r2
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C
r1r2r1+r2
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D
r1r2
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Solution

The correct option is B r1r2
The total current in the circuit is
I=2Er1+r2+R ..............................(1).....(In series, E+E=2E)
Now the potential drop across first cell is
V1=EIr1
As per the given condition
V1=0
hence,
EIr1=0
E(2Er1+r2+R)r1=0 .....................from(1)
2r1Er1+r2+R=E
r1+r2+R=2r1
R=r1r2

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