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Heating Effect of Current

Two cells of ...

Question

Two cells of unequal EMF $E_{1}$ and $E_{2}$ and internal resistances $r_{1}$ and $r_{2}$ are joined as shown in figure $V_{p}$ and $V_{q}$ are the potential at P and Q respectively.

The potential difference across both the cell will be qual

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One of the cell, will supply energy to the other cell.

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The potential difference across one of the cells will be greater than its emf

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V_{p} - V_{q} = \frac{E_{1} r_{2} + E_{2} r_{1}}{r_{1} + r_{2}}

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Solution

The correct options are
A The potential difference across both the cell will be qual
B One of the cell, will supply energy to the other cell.
D $V_{p} - V_{q} = \frac{E_{1} r_{2} + E_{2} r_{1}}{r_{1} + r_{2}}$

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Two cells of unequal EMF E1 and E2 and internal resistances r1 and r2 are joined as shown in figure Vp and Vq are the potential at P and Q respectively.

The correct options are A The potential difference across both the cell will be qual B One of the cell, will supply energy to the other cell. D Vp−Vq=E1r2+E2r1r1+r2

Two cells of unequal EMF $E_{1}$ and $E_{2}$ and internal resistances $r_{1}$ and $r_{2}$ are joined as shown in figure $V_{p}$ and $V_{q}$ are the potential at P and Q respectively.

The correct options are
A The potential difference across both the cell will be qual
B One of the cell, will supply energy to the other cell.
D $V_{p} - V_{q} = \frac{E_{1} r_{2} + E_{2} r_{1}}{r_{1} + r_{2}}$