Question

Two charged metallic spheres are joined by a very thin metal wire. If the radius of the larger sphere is twice that of the smaller one, the electric field near the larges sphere is

• A. twice that can the smaller sphere
• B. half of that near the smaller sphere
• C. the same as that near the smaller sphere
• D. one-fourth of that near the smaller sphere

Answer 1

The correct option is A twice that can the smaller sphere

Two charged metallic spheres are joined by a very thin metal wire. If the radius of the largest sphere $=2R$

$E$ $\alpha$ $\frac{1}{R^2}$ In this context we can say that twice that can the smaller sphere.