Question

Two charged particles are placed at a distance $1.0cm$ apart. What is the minimum possible magnitude of the electric force acting on each charge?

Answer 1

Minimum charge of a body is the charge of an electron
Wo, $q=1.6\times {10}^{-19}C$
$\chi =1cm=1\times {10}^{-2}$cm
So, $F=\frac{k{q}_1{q}_2}{r^2}=\frac{9\times {10}^9\times 1.6\times 1.6\times {10}^{-19}\times {10}^{-19}}{{10}^{-2}\times {10}^{-2}}=23.04\times {10}^{-38+9+2+2}=23.04\times {10}^{-25}=2.3\times {10}^{-24}$N.