Two charged particles having charge $2 \times 10^{- 8} C$ each are joined by an insulating string of length 100 cm. The system is kept on a horizontal table. Find the tension in the string.

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Solution

Here tension in the string will be equal to the
So $T = F = \frac{1}{4 π ϵ_{0}} \frac{q_{1} q_{2}}{r^{2}}$
$= 9 \times 10^{9} \times \frac{(2 \times 10^{- 8}) (2 \times 10^{- 8})}{(1)^{2}}$
$= 3.6 \times 10^{- 6} N$

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Two charged particles having charge 2×10−8C each are joined by an insulating string of length 100 cm. The system is kept on a horizontal table. Find the tension in the string.

Here tension in the string will be equal to theSo T=F=14πϵ0q1q2r2=9×109×(2×10−8)(2×10−8)(1)2=3.6×10−6N

Two charged particles having charge $2 \times 10^{- 8} C$ each are joined by an insulating string of length 100 cm. The system is kept on a horizontal table. Find the tension in the string.

Here tension in the string will be equal to the
So $T = F = \frac{1}{4 π ϵ_{0}} \frac{q_{1} q_{2}}{r^{2}}$
$= 9 \times 10^{9} \times \frac{(2 \times 10^{- 8}) (2 \times 10^{- 8})}{(1)^{2}}$
$= 3.6 \times 10^{- 6} N$