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Standard XII

Physics

Charge Behaviour

Two charged p...

Question

Two charged particles moving with velocities $v_{1}$ and $v_{2}$ have some separation between them. The ratio of magnetic force to the Colombian force between them is (c is speed of light)

\frac{v_{1} v_{2}}{c^{2}}

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\frac{c^{2}}{v_{1} v_{2}}

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\frac{c}{v_{1}}

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\frac{c}{v_{2}}

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Solution

The correct option is A $\frac{v_{1} v_{2}}{c^{2}}$

Velocities, $V_{1}$ and $V_{2}$
In this question, a most important thing is $C =$ the speed of light.
$q_{1} q_{2} α v_{1} v_{2}$
$F α q_{1} q_{2}$
So, distance will occur using the speed of light $F = \frac{q_{1} q_{2}}{c^{2}} = \frac{v_{1} v_{2}}{c^{2}}$

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Two charged particles moving with velocities v1 and v2 have some separation between them. The ratio of magnetic force to the Colombian force between them is (c is speed of light)

The correct option is A v1v2c2Velocities, V1 and V2In this question, a most important thing is C= the speed of light.q1q2αv1v2Fαq1q2So, distance will occur using the speed of light F=q1q2c2=v1v2c2

Two charged particles moving with velocities $v_{1}$ and $v_{2}$ have some separation between them. The ratio of magnetic force to the Colombian force between them is (c is speed of light)