Question

Two charged thin infinite plane sheets of uniform surface charge density ${\mathrm{\sigma }}_{+}$ and ${\mathrm{\sigma }}_{-}$, where$\left|{\mathrm{\sigma }}_{+}\right|>\left|{\sigma }_{-}\right|$, intersects at right angle. Which of the following best represents the electric field lines for this system?

• A.
• B.
• C.
• D.

Answer 1

The correct option is A

Step 1. Given data

Two charged thin infinite plane sheets of uniform surface charge density ${\mathrm{\sigma }}_{+}$ and ${\mathrm{\sigma }}_{-}$, where$\left|{\mathrm{\sigma }}_{+}\right|>\left|{\sigma }_{-}\right|$, intersects at right angle.

We have to find the electric field for this system from the given diagrams.

Step 2. Concept to be used.

The electric field lines provide information about the direction and strength of the electrical field at various place.

Step 3. Identify the electric field lines.

The electric field in each quadrant looks like as the figure below,

As the electric field due to the positive plate is greater in magnitude, so the angle made at +ve plate will be higher.

So, the final electric field will become as shown in below figure,

Since, the nearest matching option is,

Thin infinite uniformly charged planes create uniform electric field and as positive charge density is bigger in magnitude. Therefore its field along $\mathrm{y}$ axis will be bigger than the field of negative charge along the x-axis.

Hence, option $\mathrm{A}$ is correct answer.