Question

Two Charges 3*10-5 and 5*10^4 are placed at a distance in 10 cm from each other find the value of electrostatic force acting between them .

Answer 1

Dear Student,

$$\begin{gathered} Given, \\ {q}_1=3\times {10}^{-5}C \\ {q}_2=5\times {10}^{4}C \\ r=10cm=0.1m \\ F=\frac{k{q}_1{q}_2}{r^2}=\frac{9\times {10}^9\times 3\times {10}^{-5}\times 5\times {10}^4}{{(0.1)}^2}=135\times {10}^{10}N \end{gathered}$$

Regards,