Two charges +3.2×10−19 and −3.2×10−19 C placed 2.4˙A apart form an electric dipole. It is placed in a uniform electric field of intensity 4×105 volt/m. The electric dipole moment is
A
15.36×10−29Coulomb×m
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B
15.36×10−19Coulomb×m
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C
7.68×10−29Coulomb×m
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D
7.68×10−19Coulomb×m
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Solution
The correct option is C7.68×10−29Coulomb×m Dipole moment p = q (d) =3.2×10−19×(2.4×10−10)=7.68×10−29C−m