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Question

Two charges +3.2×1019 and 3.2×1019 C placed 2.4˙A apart form an electric dipole. It is placed in a uniform electric field of intensity 4×105 volt/m. The electric dipole moment is

A
15.36×1029 Coulomb×m
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B
15.36×1019 Coulomb×m
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C
7.68×1029 Coulomb×m
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D
7.68×1019 Coulomb×m
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Solution

The correct option is C 7.68×1029 Coulomb×m
Dipole moment p = q (d)
=3.2×1019×(2.4×1010)=7.68×1029Cm

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