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Question

Two charges 4q and q are placed at a distance apart. An another charged particle Q is placed in between them (at mid point). If resultant force on q is zero then the value of Q is

A
q
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B
q
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C
2q
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D
2q
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Solution

The correct option is B q

The force due to +4q on +q is given as,

F1=14πε0×4q×ql2

The force due to Q on +q is given as,

F2=14πε0×Q×q(l2)2

If the resultant force is zero, then the force due to Q should be opposite to the force due to +4q.

Therefore, the charge Q should be negative.

The magnitudes of the two forces should be the same and it can be written as,

14πε0×4q×ql2=14πε0×Q×q(l2)2

Q=q

Thus, the value of Q is q.



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