Question

Two charges are placed at a distance apart. If a glass slab is placed between them, force between them will

• A. be zero.
• B. increase.
• C. decrease.
• D. remains the same.

Answer 1

The correct option is C decrease.

$F=\frac{q_1{q}_2}{4\pi ϵk{r}^2}$ where k is dielectric constant and $k_{glass}>k_{air}$