Question

Two charges are separated by a distance d. If the distance between them is doubled, how does the electric potential between them change?

• A. It is doubled
• B. It is halved
• C. It is quartered
• D. It is quadrupled
• E. It is unchanged

Answer 1

The correct option is B It is halved

Initial electric potential between the charges $V=\frac{kq}{d}$

New distance between the charges $d^{\prime }=2d$

Thus new electric potential $V^{\prime }=\frac{kq}{2d}=\frac{V}{2}$