Question

Two charges each equal to $2\mu C$ are 0.5m apart. If both of them exist inside vacuum, then the force between them is

• A. 1.89 N
• B. 2.44 N
• C. 0.144 N
• D. 3.144 N

Answer 1

Answer: (C)

Step 1, Given data

Charges = $2\mu C=2\times {10}^{-6}C$

Distance = 0.5 m

Step 2, Finding the force

From the law, we know,

The electrostatic force is given as

$F=9\times {10}^9.\frac{Q^2}{r^2}$ ( As both charges are equal)

Putting all the values

$\Rightarrow F=9\times {10}^9.\frac{(2\times {10}^{-6}{)}^2}{(0.5{)}^2}=0.144N$

Hence the force between the charges is 0.144 N