Two charges of 10μC and −20μC are separated by a distance of 20 cm. The distance of the point from 10μC where electric potential is zero, if it lies between them is
A
320 cm
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B
6.67 cm
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C
10 cm
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D
16 cm
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Solution
The correct option is B6.67 cm Let x be the distance form 10μC where potential is zero. ⇒0=k(10μC)x+k(−20μC)20−x ⇒0=10x−2020−x ⇒(20−x)10=20x ⇒20=3x x=203=6.67 cm