Two charges of 40μC and 90μC are placed at a distance of 1m from each other. Where should a third charge be placed on the line joining them, if total force on the third charge is zero?
A
In between, 40cm from 90μC
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B
In between, 40cm from 40μC
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C
In between, 50cm from 40μC
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D
In between, 20cm from 90μC
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Solution
The correct option is B In between, 40cm from 40μC
Here, l=1m Net force on charge q=0 ⇒k(40×10−6)qx2=k(90×10−6)×q(1−x)2 ⇒4(1−x)2=9x2 ⇒x=25m=40cm