Two charges of 6 - C and 24 - C are placed 12 cm apart- The intensity of the electric field is zero- at a pointA- 4 cm from the smaller charge and the point insideB- 4 cm from the smaller charge and the point outsideC- 4 cm from the bigger charge towards the smaller chargeD- 12 cm from both charges

The correct option is A 4 cm from the smaller charge and the point inside x=d/√(q_2/q_1)+1=12/√(24/6)+1=12/2+1=12/3=4 cm x = 4 cm from the smaller charge, poin ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Electric Field Due to a Line of Charge Not on Its Axis

Two charges o...

Question

Two charges of 6 $μ C$ and 24 $μ C$ are placed 12 cm apart. The intensity of the electric field is zero, at a point

4 cm from the smaller charge and the point inside

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

4 cm from the smaller charge and the point outside

No worries! We‘ve got your back. Try BYJU‘S free classes today!

12 cm from both charges

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 cm from the bigger charge towards the smaller charge

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 4 cm from the smaller charge and the point inside
$x = \frac{d}{\sqrt{\frac{q_{2}}{q_{1}}} + 1} = \frac{12}{\sqrt{\frac{24}{6}} + 1} = \frac{12}{2 + 1} = \frac{12}{3} = 4 c m$
x = 4 cm from the smaller charge, point inside

Suggest Corrections

Similar questions

Two point charges 2 μC and 8μC are placed 12 cm apart. The position of point from 2 μC charge, where the electric field intensity is zero is:

Q. Two charges

4 μ C

and

36 μ C

are placed

60 c m

apart. At what distance from the larger charge is the electric field intensity is zero?

Q. Positive charges of

2

μ

C and

8

μ

C are placed

15 c m

apart. At what distance from the smaller charge will be electric field due to them be zero?

Two electric charges $12 μ C$ and $- 6 μ C$ are placed $20 c m$ apart in air. There will be a point P, at which electric potential is zero on the line joining these two charges and outside excluding the region between them. The distance of P from $- 6 μ C$ charge is:

Q. Two electric charges

12 μ C

and

- 6 μ C

are placed 20 cm apart in air. There will be a point P on the line joining these charges and outside the region between them, at which the electric potential is zero. The distance of P from

- 6 μ C

charge is

Join BYJU'S Learning Program

Two charges of 6 μC and 24 μC are placed 12 cm apart. The intensity of the electric field is zero, at a point

The correct option is A 4 cm from the smaller charge and the point inside x=d√q2q1+1=12√246+1=122+1=123=4 cm x = 4 cm from the smaller charge, point inside

Two charges of 6 $μ C$ and 24 $μ C$ are placed 12 cm apart. The intensity of the electric field is zero, at a point

The correct option is A 4 cm from the smaller charge and the point inside
$x = \frac{d}{\sqrt{\frac{q_{2}}{q_{1}}} + 1} = \frac{12}{\sqrt{\frac{24}{6}} + 1} = \frac{12}{2 + 1} = \frac{12}{3} = 4 c m$
x = 4 cm from the smaller charge, point inside