Question

Two charges of equal magnitudes and at a distance r exert a force F on each other. If the charges are halved and distance between them is doubled, then the new force acting on each charge is

• A. $\frac{F}{8}$
  
• B. $\frac{F}{4}$
  
• C. $4F$
  
• D. $\frac{F}{16}$

Answer 1

The correct option is D $\frac{F}{16}$

$F=k.\frac{Q^2}{r^2}$. If Q is halved, r is doubled then $F\to \frac{1}{16}$ times