Two charges of magnitude -4C and 4C are placed at points (1, 2, 3) and (3, 4, 2) respectively. What is the dipole moment?

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Solution

The correct option is C
The dipole moment will be in the direction of the vector connecting -4C to 4C i.e., from (1, 2, 3) to (3, 4, 2).
Let $\to L \to$ which is a vector representing the distance between -4C charge to +4C Charge
$\to L$ = Portion vector of +4C charge – Position vector of -4C charge.

$\to L$ = $(3 ˆ i + 4 ˆ j + 2 ˆ k) - (1 ˆ i + 2 ˆ j + 3 ˆ k)$
$= 2 ˆ i - 2 ˆ j - ˆ k$
Now $\to p$ = $q \to L = 4 \times (2 ˆ i - 2 ˆ j - k)$
$= 8 ˆ i - 8 ˆ j - 4 ˆ k$

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