Two charges- Q 1-7-00 - C and Q 2-5-00 - C are 0-03 m apart- How much work in joule is done in bringing a third charge of -5-00 - C to form the third vertex of an equilateral triangle- 0-03 m from each of the other charges-

Let the said arrangement be as shown in the below figure Given, Q_1 = + 7.00 μ C, Q_2 = 5.00 μ C and nbsp;Q_3=+ 5.00 μ C We know that the work done is give ...

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Standard XII

Physics

Properties of Charges

Two charges, ...

Question

Two charges, $Q_{1} = + 7.00 μ C$ and $Q_{2} = - 5.00 μ C$ are $0.03 m$ apart. How much work (in joule) is done in bringing a third charge of $+ 5.00 μ C$ to form the third vertex of an equilateral triangle, $0.03 m$ from each of the other charges?

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Solution

Let the said arrangement be as shown in the below figure

Given, $Q_{1} = + 7.00 μ C$ , $Q_{2} = - 5.00 μ C$ and $Q_{3} = + 5.00 μ C$
We know that the work done is given by
$W_{ext} = Δ U$
$\Rightarrow \frac{K Q_{1} Q_{3}}{r_{1}} + \frac{K Q_{2} Q_{3}}{r_{2}}$

$\Rightarrow \frac{K Q_{1} Q_{3}}{0.03} + \frac{K Q_{2} Q_{3}}{0.03}$

$\Rightarrow \frac{9 \times 10^{9} \times (+ 5) \times 10^{- 6}}{3 \times 10^{- 2}} \times (7 - 5) \times 10^{- 6} = 3 J$

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Two charges, Q1=+7.00 μC and Q2=−5.00 μC are 0.03 m apart. How much work (in joule) is done in bringing a third charge of +5.00 μC to form the third vertex of an equilateral triangle, 0.03 m from each of the other charges?

Let the said arrangement be as shown in the below figure Given, Q1=+7.00 μC, Q2=−5.00 μC and Q3=+5.00 μC We know that the work done is given by Wext=ΔU ⇒ KQ1Q3r1+KQ2Q3r2 ⇒ KQ1Q30.03+KQ2Q30.03 ⇒ 9×109×(+5)×10−63×10−2×(7−5)×10−6=3 J

Two charges, $Q_{1} = + 7.00 μ C$ and $Q_{2} = - 5.00 μ C$ are $0.03 m$ apart. How much work (in joule) is done in bringing a third charge of $+ 5.00 μ C$ to form the third vertex of an equilateral triangle, $0.03 m$ from each of the other charges?