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Question

Two charges q1 and q2 are located 30 cm apart, as shown in the figure. A third charge q3 is moved along tthe arc of a circle of radius 40 cm from C to D. The change in the potential energy of the system is nq2q34πϵ0. Find n.


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Solution

Ui=14πϵ0[q1q3(0.4)+q1q2(0.3)+q2q3(0.5)]
Uf=14πϵ0[q1q30.4+q1q20.3+q2q30.1]
ΔU=UfUi=q2q34πϵ0(10.110.5)
=q34πϵ0(8q2)

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