Two charges $Q_{1}$ and $Q_{2}$ are placed in vacuum at a distance d and the force acting between them is $5$ units. If a medium of dielectric constant $2$ is introduced around them, the net force now will be :

10

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2.5

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5

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infinite

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Solution

The correct option is C $2.5$
when dielectric is added $ε_{0}$ becomes $k ε_{0}$
where $k$ is dielectric constant
we known $F_{i} = \frac{1}{4 π ε_{0}} \frac{Q_{1} Q_{2}}{r^{2}}$
when dielectric is added $f_{f} = \frac{1}{4 π k ε_{0}} \frac{Q_{1} Q_{2}}{r^{2}}$
$∴ F_{f} = \frac{5}{2}$ $= 2 \cdot 5 u n i t s$

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