Two charges q1 and q2 are placed 30 cm apart as shown. A third charge q3 is moved along the arc of a circle of radius 40 cm from C to D. The change in the potential energy of the system is $\frac{q_{3}}{4 π \in_{0}} k$ , where k is

8 q_{2}

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8 q_{1}

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6 q_{2}

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6 q_{1}

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Solution

The correct option is A $8 q_{2}$

Change in potential energy $(Δ U) = U_{f} - U_{t}$
$\Rightarrow Δ U = \frac{1}{4 π \in_{0}} [(\frac{q_{1} q_{3}}{0.4} + \frac{q_{2} q_{3}}{0.1}) - (\frac{q_{1} q_{3}}{0.4} + \frac{q_{2} q_{3}}{0.5})]$
$\Rightarrow Δ U = \frac{1}{4 π \in_{0}} [8 q_{2} q_{3}] = \frac{q_{3}}{4 π \in_{0}} (8 q_{2})$
$∴ k = 8 q_{2}$

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Similar questions

Q. Two charges

q_{1}

and

q_{2}

are placed

30 cm

apart, as shown in the figure. A third charge

q_{3}

is moved along the arc of a circle of radius

40 cm

from

C

D

. The change in the potential energy of the system is

\frac{q_{3}}{4 π ϵ_{0}} k

, where

k

Two charges $q_{1}$ and $q_{2}$ are placed 30cm apart, as shown in figure. A third charges $q_{3}$ is moved along the arc of a circle of radius 40 cm from C to D. The change in the potential energy of the system is $\frac{q_{3}}{4 π ϵ_{0}} k$ , where k is