wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two children are at opposite ends of an iron pipe. One strikes his end of the iron pipe with a stone. Find the ratio of times taken by the sound wave in air and in iron to reach the other child. Given, velocity of sound in air is 344 ms−1 and that in iron is 5130 ms−1.

A
t1t2=14.3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
t1t2=11.9
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
t1t2=14.9
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
t1t2=10.4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C t1t2=14.9
Here, the distance travelled by sound waves through air and iron is same which is equal to the thickness (s) of the rod.

For air, jet the speed be v1 and time be t1.

For iron, let the speed be v2 and time be t2.

Now, v1=st1ors=v1t1 ...(1)

Also, v2=st2ors=v2t2 ...(2)

From (1) & (2), we get, v1t1=v2t2

t1t2=5130344=14.9

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Speed of Sound
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon