Two chords AB and CB of a circle are at equal distances from the centre of the circle. Then, △ABC is an isosceles triangle.
A
True
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B
False
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Solution
The correct option is A True Consider a circle centered at O. Given, two chords AB and CB of a circle are at equal distances from the centre of the circle. i.e., In the above figure OM = ON. We know that the chords of a circle equidistant from the centre of a circle are congruent. Hence, AB = CB. ∴△ABC is isosceles. So, the given statement is true.