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Question

Two chords AB and CB of a circle are at equal distances from the centre of the circle. Then, ABC is an isosceles triangle.

A
True
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B
False
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Solution

The correct option is A True
Consider a circle centered at O.
Given, two chords AB and CB of a circle are at equal distances from the centre of the circle.
i.e., In the above figure OM = ON.
We know that the chords of a circle equidistant from the centre of a circle are congruent.
Hence, AB = CB.
ABC is isosceles.
So, the given statement is true.

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