Question

Two chords AB and CD intersect at point O inside the circle. If OA = 5 cm, OB = 6 cm and OC = 3 cm, then find the value of CD.

Answer 1

When two chords intersect each other in a circle, the product of the chord segments will be equal.
So, $OA\times OB=OD\times OC$
$5\times 6=OD\times 3$
$OD=10cm$
$CD=OC+OD=3+10=13cm$