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Question

Two chords intersect at a point on a circle and the diameter through this point bisects the angle between the chords. Then the chords have the same length.

A
True
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B
False
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Solution

The correct option is A True
In OEB&OEC, they are congruent (SAS)
Three lines are concurrent at E.
Three vertically opposite angles are same. Let them be p, q, r.
BE=EC(1)
AEO&DEO are congruent too (SAS)
DE=AE(2)
Total lengths of chord
AE+EC=DE+EB (Same) (From (1) &(2))
Hence, True.

983621_1048949_ans_e5e8b96d7a87496b898c4bd78fd01168.png

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