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Question

Two chrges 5 μC and 4 μC are separated by a distance 20 cm in air work to be done to decrease the distance to 10 cm is

A
0.9 J
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B
1.8 J
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C
9 J
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D
18 J
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Solution

The correct option is A 0.9 J
Given, q1=5 μCq2=4 μCr1=20 cm=20×102 mr2=10 cm=10×102 m

Work done W=ΔU

Ui=14πε0q1q2r1

=9×109×5×106×4×10620×102

=9×101 J=0.9 J

Uf=14πε0q1q2r2

=9×109×5×106×4×10610×102

Uf=18×101 J=1.8 J

W=UfUi

=1.80.9=0.9 J

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (a) is the correct answer.

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