Two circles intersect at points A and B.The points P and Q are the other ends of the diameter through A
Then P,B,Q
lies on a straight line
Join AP,PB and BQ
In △ABP and △ABQ
∠ABP=∠ABQ=90∘ (angle in semi-circle)
∠ABP+∠ABQ=90+90=180∘
So,PBQ is a straight line.
So,P,B,Q lies on a straight line.