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Question

Question 9
Two circles intersect at two points B and C. Through B, two line segments ABD and PBQ are drawn to intersect the circles at A, D and P, Q respectively (see the given figure). Prove that ACP=QCD

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Solution


Construction:
Join chords AP and DQ.

For chord AP,
PBA=ACP (Angles in the same segment) ... (1)
For chord DQ,
DBQ=QCD (Angles in the same segment) ... (2)
ABD and PBQ are line segments intersecting at B.
PBA=DBQ (Vertically opposite angles) ... (3)
From equations (1), (2), and (3), we obtain
ACP=QCD


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