Two circles intersect in A and B. Quadrilaterals PCBA and ABDE are inscribed in thesecircles such that PAE and CBD are line segments. ∠P=950 and∠C=400.Find the value of Z.
850
In PABC,
∠P+∠B=180∘
⇒∠B=180∘−95∘=85∘
∠CBD=180∘ ( Linear pair)
So, ∠DBA=180∘−85∘=95∘
In ABDE,
∠B+∠E=180∘⇒∠E=Z∘
Z∘=180∘−95∘=85∘