Question

Two circles of radii $4$ cm and $14$ cm have a common external tangent of length $24$ cm The distance between the centres of these circles (in cm) is

• A. $24$
• B. $25$
• C. $26$
• D. $27$

Answer 1

The correct option is C $26$

Horizontal distance between the centre of two circle = 24 cm
Vertical distance between the centre of two circle = 10 cm
Now, let the distance between the two centres is $r$
The, $r^2={24}^2+{10}^2$ (Pythagoras Theorem)
$r=\sqrt{576+100}$
$r=26$ cm