Two circles of radius 3 cm each is constructed such that centre of each touches the circumference of other as shown in figure. The triangle A C1 C2 is
Since the radius of the circle is the same , we have
AC2=AC1=r
C1 C2 = is also equal to radius of the circle
Hence, AC1=AC2=C1 C2=r
∴ The triangle formed is an equilateral triangle.