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Question

Two circles touch each other externally at a point C and P is a point on the common tangent at C. If PA and PB are tangents to the two circles, prove that PA = PB.


Solution

We know that,

PC = PB  (Tangents drawn from the same external point to a circle are equal)

Also,

PC = PA   (Tangents drawn from the same external point to a circle are equal)

Hence, from the above two equations, 

PA = PB

Hence, Proved.


Mathematics

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