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Question

Two circles touch each other externally. The sum of their areas is (106π)cm2 and the distance between their centers is 14 cm. Find the individual diameters of the circles.


A

12cm and 6cm

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B

18 cm and 10cm

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C

10cm and 7cm

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D

9cm and 5cm

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Solution

The correct option is B

18 cm and 10cm


Let the radii of bigger and smaller circles be 'R' and 'r' respectively.

Sum of areas =πR2+πr2=π(R2+r2)

According to question, π(R2+r2)=106π

R2+r2=106(I)

Also, R+r=14

R=14r(II)

Putting (II) in (I)

(14r)2+r2=106

196+r228r+r2=106

2r228r+90=0

r214r+45=0

r29r5r+45=0

r(r9)5(r9)=0

(r5)(r9)=0

r=9 or r=5

r=9 cm is not possible because that would mean R=5 cm which does not hold true for our assumption. So, r=5 cm and R=9 cm. Individual diameters of the two circles = 18cm and 10 cm


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