Two circles touch each other externally. The sum of their areas is (106π)cm2 and the distance between their centers is 14 cm. Find the individual diameters of the circles.
18 cm and 10cm
Let the radii of bigger and smaller circles be 'R' and 'r' respectively.
Sum of areas =πR2+πr2=π(R2+r2)
According to question, π(R2+r2)=106π
⇒R2+r2=106−−−(I)
Also, R+r=14
⇒R=14−r−−−−(II)
Putting (II) in (I)
(14−r)2+r2=106
196+r2−28r+r2=106
2r2−28r+90=0
r2−14r+45=0
r2−9r−5r+45=0
r(r−9)−5(r−9)=0
(r−5)(r−9)=0
r=9 or r=5
⇒r=9 cm is not possible because that would mean R=5 cm which does not hold true for our assumption. So, r=5 cm and R=9 cm. Individual diameters of the two circles = 18cm and 10 cm