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Question

Two circles touch internally. The sum of their areas is 116π sq. cm and the distance between their centers is 6 cm. The radii of the given circles are

A
8cm & 20cm.
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B
4cm & 10cm.
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C
6cm & 8cm
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D
5cm & 9cm.
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Solution

The correct option is B 4cm & 10cm.
GivenTwocirclestouchinternally.Thedistancebetweentheircertres=6cm.Theradiioftheouter&innercirclesarer2&r1respectively.Thesumoftheirareas=116π.

Tofindout(r2&r1)=?
SolutionSincethecirclestouchinternally,thedistancebetweentheircertres=thedifferencecebetweentheirradii=6cm.

r2r1=6cmr2=r1+6.Soar.outercircle=π×(r2)2=π×(r1+6)2.Andar.innercircle=π×(r1)2.

Thesumoftheirareas=π×(r1+6)2+π×(r1)2=116π.(r1)2+6r40=0(r1+10)(r14)=0r1=(10,4)cm.
Werejectthenegativevalueofr1sincer1isalength.r1=4cm.Sor2=(r1+6)cm=(4+6)cm=10cm.r1=4cm,r2=10cm.

AnsOptionB.

333307_241820_ans_de04aa3f0cb64bb5b776ac30847e2b24.png

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