Two circuits have mutual inductance of $0.1 H .$ What average e.m.f. is induced in one circuit when the current in the other circuit changes from $0$ to $20 A$ in $0.02 s$

240 V

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230 V

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100 V

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300 V

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Solution

The correct option is C $100 V$
$e = M \frac{d i}{d t}$

$\Rightarrow e = 0.1 \times \frac{(20 - 0)}{0.02} = 100 V$

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Two circuits have mutual inductance of 0.1H. What average e.m.f. is induced in one circuit when the current in the other circuit changes from 0 to 20A in 0.02s

The correct option is C 100Ve=Mdidt⇒e=0.1×(20−0)0.02=100V

Two circuits have mutual inductance of $0.1 H .$ What average e.m.f. is induced in one circuit when the current in the other circuit changes from $0$ to $20 A$ in $0.02 s$

The correct option is C $100 V$
$e = M \frac{d i}{d t}$

$\Rightarrow e = 0.1 \times \frac{(20 - 0)}{0.02} = 100 V$