Two circular coils of radii 10 cm and 40 cm and equal number of turns are connected in series to a battery. The ratio of magnetic fields at their centres is

1: 4

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4:1

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2: 1

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1: 2

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Solution

The correct option is B 4:1
We know,

$B = \frac{μ_{0} I n}{4 R}$

As the loops are connected in series, both loop will have same current,
and also they have same no. of turns.

Then,

$B \propto \frac{1}{R}$

$B_{10} : B_{40} = \frac{40}{10} = 4 : 1$

Option $B$ is the correct answer.

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Two circular coils of radii 10 cm and 40 cm and equal number of turns are connected in series to a battery. The ratio of magnetic fields at their centres is

The correct option is B 4:1We know,B=μ0In4RAs the loops are connected in series, both loop will have same current,and also they have same no. of turns.Then,B∝1RB10:B40=4010=4:1Option B is the correct answer.

The correct option is B 4:1
We know,

$B = \frac{μ_{0} I n}{4 R}$

As the loops are connected in series, both loop will have same current,
and also they have same no. of turns.

Then,

$B \propto \frac{1}{R}$

$B_{10} : B_{40} = \frac{40}{10} = 4 : 1$

Option $B$ is the correct answer.