Two circular discs A and B are of equal masses and thicknesses but made of metal with densities dA and dB (dA>dB). If their moments of inertia about an axis passing through their centres and perpendicular to circular faces are IA and IB
A
IA=IB
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B
IA>IB
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C
IA<IB
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D
IA≥IB
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Solution
The correct option is CIA<IB Since the masses of the two discs are equal we see that for the disc A which has a higher density will have smaller radius to keep the product of volume x density equal. Thus rA<rB, thus we get IA<IB