Two cities A and B are at a distance of 60 km from each other. Two persons P and Q start from the first city at a speed of 10 km/hr and 5km/hr respectively. P reached the second city B and returns to meet Q at Y. Find the distance between A and Y.
A
30 km
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B
40 km
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C
50 km
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D
55 km
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E
53 km
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Solution
The correct option is B 40 km Time taken by P to reach city B is 6hr. In 6 hr, distance covered by Q is 30 km. Now at some x distance they will meet. So x5=30−x10⇒x=10 So distance between A and Y is 30+10 = 40km