Question

Two cities $P$ and $Q$ are $110$ $km$ apart. Person $A$ started from city $P$ at $7$ $a.m.$ at the speed of $20$ $km/hr$ and $B$ started from city $Q$ at $8$ $a.m.$ at the speed of $25$ $km/hr,$ they meet at

• A. $9$ $a.m.$
• B. $10$ $a.m.$
• C. $12$ $a.m.$
• D. $11$ $a.m.$

Answer 1

Answer: (B)

$10$ $a.m.$

Distance between $P$ and $Q$ at $7a.m.=110Km$

Distance between $P$ and $Q$ at $8a.m.=110-20=90km$

So,Now both Person have to travel 90 km combinely

$90=20T+25T$

$T=$ $2hrs$

Therefore, Time of Meeting $=8:00+2:00=10:00am$

Therefore Answer is $\left(B\right)$