wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two closed bulbs of equal volumes (V) containing an ideal gas initially at pressure pi and temperature T1 are
connected through a narrow tube of negligible volume as shown in the figure below. The temperature of one of the bulbs is then raised to T2. The final pressure pf is:

A
2pi(T1T1+T2)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2pi(T2T1+T2)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2pi(T1T2T1+T2)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
pi(T1T2T1+T2)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 2pi(T2T1+T2)
Initial total moles:

n=piVRT1+piVRT1=2piVRT1(1)

Final total moles:

n=pfVRT1+pfVRT2(2)

Equating the two:

2piT1=pfT1+pfT2

pf=2piT1×T1T2(T1+T2)

pf=2pi×T2(T1+T2)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon