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Byju's Answer

Standard XII

Chemistry

System, Surroundings, Intensive, Extensive Properties

Two closed ve...

Question

Two closed vessels of equal volume containing air at pressure $P_{1}$ and temperature $T_{1}$ are connected to each other through a narrow tube. If the temperature in one of the vessels is now maintained at $T_{1}$ and that in the other at $T_{2}$ , what will be the pressure in the vessels

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Solution

The correct option is C
Initially, pressure in each vessel = $P_{1}$
And,finally pressure in each vessal = P
$\frac{P_{1}}{T_{1}} + \frac{P_{1}}{T_{1}} = \frac{P}{T_{1}} + \frac{P}{T_{2}}$
$\frac{2 P_{1}}{T_{1}} = P (\frac{T_{1} + T_{2}}{T_{1} T_{2}})$ ;
$∴ P = \frac{2 P_{1} (T_{1} T_{2})}{T_{1} (T_{1} + T_{2})} = \frac{2 P_{1} T_{2}}{T_{1} + T_{2}}$

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and that in the other at

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, what will be the pressure in the vessels?

Q. Two closed vessel

A

and

B

of equal volume containing air at pressure

P_{1}

and temperature

T_{1}

are connected to each other through a narrow open tube. If the temperature of one is now maintained at

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Two closed vessels of equal volume containing air at pressure P1 and temperature T1 are connected to each other through a narrow tube. If the temperature in one of the vessels is now maintained at T1 and that in the other at T2, what will be the pressure in the vessels

The correct option is C Initially, pressure in each vessel = P1 And,finally pressure in each vessal = P P1T1+P1T1=PT1+PT2 2P1T1=P(T1+T2T1T2); ∴P=2P1(T1T2)T1(T1+T2)=2P1T2T1+T2

Two closed vessels of equal volume containing air at pressure $P_{1}$ and temperature $T_{1}$ are connected to each other through a narrow tube. If the temperature in one of the vessels is now maintained at $T_{1}$ and that in the other at $T_{2}$ , what will be the pressure in the vessels