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Standard XII

Physics

Fringe Width in YDSE

Two coherent ...

Question

Two coherent light sources $S_{1}$ and $S_{2} (λ = 6000 o A)$ are 1 mm apart from each other. The screen is placed at a distance of 25 cm from the sources. The width of the fringes on the screen should be

0.015 c m

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0.025 c m

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0.030 c m

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0.10 c m

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Solution

The correct option is A $0.015 c m$
We know $β = \frac{D λ}{2 d}$ ,
Given, $λ = 6000 o A = 6000 \times 10^{- 8}$ cm
$D = 25$ cm
and $2 d = 1 m m = 0.1$ cm
$∴ β = \frac{6000 \times 10^{- 8} \times 25}{0.1} = 0.015 c m$

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Two coherent light sources S1 and S2(λ=6000oA) are 1 mm apart from each other. The screen is placed at a distance of 25 cm from the sources. The width of the fringes on the screen should be

The correct option is A 0.015cmWe know β=Dλ2d,Given, λ=6000oA=6000×10−8 cmD=25 cmand 2d=1mm=0.1 cm∴β=6000×10−8×250.1=0.015cm

Two coherent light sources $S_{1}$ and $S_{2} (λ = 6000 o A)$ are 1 mm apart from each other. The screen is placed at a distance of 25 cm from the sources. The width of the fringes on the screen should be

The correct option is A $0.015 c m$
We know $β = \frac{D λ}{2 d}$ ,
Given, $λ = 6000 o A = 6000 \times 10^{- 8}$ cm
$D = 25$ cm
and $2 d = 1 m m = 0.1$ cm
$∴ β = \frac{6000 \times 10^{- 8} \times 25}{0.1} = 0.015 c m$