CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Single Slit Diffraction

Two coherent ...

Question

Two coherent lights beams of intensity $I$ and $4 I$ are superposed. The minimum and maximum possible intensities in the resultant beam are :

A

9 I

and

I

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B

9 I

and

3 I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

5 I

and

I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

5 I

and

3 I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $9 I$ and $I$
$\frac{I_{m a x}}{I_{m i n}} = (\frac{\sqrt{4 I} + \sqrt{I}}{\sqrt{4 I} - \sqrt{I}})^{2} = \frac{9}{1}$

Suggest Corrections

thumbs-up

0

Similar questions

Q. Two coherent light beams of intensity I and 4I are superposed. The maximum and minimum possible intensities in the resulting beam are.

Q. Two coherent monochromatic light beams of intensities 4I and 9 I are superposed. The maximum and minimum possible intensities in the resulting beam are

Q. Two coherent light beams of intensities I and 4I are superposed. The maximum and minimum possible intensities in the resulting beam are :

Q. Two coherent monochromatic light beams of intensities '

4 I

9 I

' are superimposed. The maximum and minimum possible intensities in the resulting beam are

Q. Two coherent monochromatic light beams of intensities

I

4 I

are superposed. The maximum and minimum possible resulting intensities are :

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Diffraction I

PHYSICS

Watch in App

explore_more_icon

Explore more

Single Slit Diffraction

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon